Analyst Interview Questions | Glassdoor.co.uk

# Analyst Interview Questions

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Analyst interview questions shared by candidates

## Top Interview Questions

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### Summer Securities Analyst at Goldman Sachs was asked...

30 Jan 2016
 Assume you are the people who help balance between student campus and the society. The student campus set a budget of 50%, but the society set a budget of 75% after conference. And both of them don't want to decrease their budget. What will you do ? 22 AnswersI have done the same interview with the same questions , probably the same day. Have you already received an email or something? I'm struggling! Thank you , it is great to have someone to share with this challenging experiencei have not yet received any email as it seems that it will take a couple of weeks to review. Just wait I think.Got a similar question. Interviewed on the 26th of January. Will hear back in a couple of weeks too! Really scared.Show more responsesHave anyone heard back yet?Nope.... will hear back this week! have you heard back?Nope :(Nope!How did you know that we'll hear back this week? Still haven't heard back :(have heard back already!have you?has anyone else heard back??Have heard back too!and what is the answer to the question?Show more responsesWhen did they get back to you?still have not heard back nothing, how is it possible? positive or negative outcome?Got the offer!I also haven't heard backDo they write even if the outcome is negative? I still hope but...Frustrated, another week without newsNews? I don't know what I have to do....Still no response...mee too!

28 Jun 2014

13 May 2013

### Quantitative Analyst at Goldman Sachs was asked...

21 Mar 2012
 a, b, c are integers. Such that a^2 + 2bc = 1; b^2 + 2ac=2012, find all the possibles values of c^2 + 2ab. 7 Answers2011 is primeMore details in addition to the last post. 1) subtracting the 1st equation from the 2nd one gives: (b-a)*(b+a-2c)＝2011 2) 2011 is prime, so there are only two possibilities: b-a=1, b+a-2c=2011; or b-a=2011, b+a-2c=1 3) subtracting the 1st equation from the 3rd equation gives: (c-a)(c+a-2b)=x-1 4) plugging c-a=0.5*[(b-a)-(b+a-2c)], c+a-2b=(c-a)-2(b-a) into 3) gives you xIn 2) there should be four rather than two possibilities. Both terms could be negative.Show more responses2 cand: heavy one... I have no idea how did you figure out that 2011 is prime! Do you remember the table of prime numbers from 2 to 10000?? I easily found trivial solution b=0 a=+-1, and then got stucked. however, later I found that this is unique solution, and (3)=c^2= 1006^2. I've used your approach. You've got a 4 possibilities, +-1 +-2011 and +-2011 +-1, but 2 of them lead to complex roots. You see, sum (1)+(2)+(3) gives you (a+b+c)^2=1+2012+x, thus x>=-2013, so (b-a) may be only +-1, not +-2011. The answer is (3)=1012036In the equation a^2 + 2bc = 1, obviously, a is either 1 or -1 and either b or c is zero. Then if you derive b from the second equation, b = sqrt(2012 - 2ac), c can't be zero, because sqrt(2012) is not an integer. Therefore b = 0. So, in order for b to be 0, 2012 - 2ac should be zero or 2ac = 2012. => it's either a = -1 and c = -606 or a =1 and c = 606. In any case, because b is zero, 2bc term in the 3rd equation disappears and c^2 gives an answer 367236.To the comment above, 2ab term in the 3rd equation, of coursesimple eq: (a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca. from given eq, we know: (a+b+c)^2 = (2012 + 1 + UNKNOWN) = K^2 with K being anything larger than 45. 45*45 = 2025 46*46 = 2116 .. so you can figure out the missing term by: (K^2 - 2013)

26 Nov 2016

### Quantitative Analyst at Morgan Stanley was asked...

4 Nov 2011
 You have a deck of 52 cards, and you keep taking pairs of cards out of the deck. if a pair of cards are both red, then you win that pair; if a pair of cards are both black, then I win that pair; if a pair of cards has one red and one black, then it's discarded. If, after going through the whole deck, you have more pairs than I do, then you win \$1, and if I have more pairs than you do, I win \$1. What is the value of this game in the long run?7 Answers00 lol. nice oneby symmetry, probability of losing = probability of winning therefore, -1p(lose)+1p(win)=0. done, ko, finished, fiendin'Show more responsesNo one bothered to ask if you're paying the loser -- e.g. when you win, you get \$1, but when you lose, are you losing \$1? It's not clear from the question above, though the interviewer may have been more specific.good point J.D It can either be 0 or 0.5 depending on how you interpret the questionI think you will always have the same number of pairsWhy is it 0 for us dumb people pls

1 Jan 2010

### Research Analyst at Nielsen was asked...

8 Jul 2010
 How many bottles of beer are drank in the city over the week.6 Answers0, none - this is a dry city!I think the answer is 0. I think the problem with this is the word drank, and the fact that it is preceded with a helping verb, which happens to be in the wrong tense. I think the proper question would be "How many bottles of beer were drunk in the city over the week". Or "How many bottles of beer are drunk in the city over a week".n + (7 * 12) where n = whatever the rest of the city is drinking and 7 * 12 = the twelve pack I sink every day Any more (brap) questions? RstJShow more responsesMr. Nielson, your grammar is slipping. That's enough beer for now. May I call a taxi for you?measure how fugugly the chicks are consult recyclers and survey the city dump trucksquite an answer RstJ....but the question itself doesn't make any sense even grammatically.. ..

13 Oct 2014