Sr software engineer Interview Questions

//need to use and also "/*" and "*/" need to be followed by space " ". int main() { string s = "hello /* this is a multi line comment */ all "; istringstream iss(s); string tmp; while(iss>>tmp){ if(tmp=="/*"){ while(iss>>tmp){ if(tmp=="*/"){ iss>>tmp; break; } } } cout<

def echo(what): sys.stdout.write(what) def gobble(what): pass funsrc = cycle([(echo, "/*"), (gobble, "*/")]) consumer_fun, delim = funsrc.next() while True: line = getNextLine() if not line: break ix = line.find(delim) while ix >= 0: prefix = line[:ix] line = line[ix+len(delim):] consumer_fun(prefix) consumer_fun, delim = funsrc.next() ix = line.find(delim) consumer_fun(line)

import re lines = [] while True: line = getNextLine() if line == None: break lines += line print re.sub(r'/\*(.|\n)*?\*/','',lines.join('\n'))

I don't think they are really recruiting anyone people. In my case, they just told me that my code did not pass by their internal assessment system. But, they did not say what wrong in my code and why it is failed.

Sat the refactoring test and had no feedback. Chased the Job Recruiter who is never at his desk. How strange. Clear Bank are a waste of time, I would keep clear.

refactored using SOLID principles.

It was hard to write under pressure. Basically, I was using HashMap. Key for integer, value for spelling. Solution you can find somewhere at leetcode

haven't checked leetcode, but how about this? firstly use (int)(Math.log10(number) + 1) to get the number of digits in the given number. (Note: you have to handle 0 differently) e.g 16138832 should return 8. Use this number of digits to get an idea of digit place's spelling (billion, million, thousand, hundred) Then for each digit (0~9) I'm thinking of using the previous answer's suggestion of HashMap to get the spelling. So I imagine there would be two HashMaps, one for getting the digit spelling (one, two, ... nine, ten, ... , nineteen), the other for the digit place spelling (billion, million, thousand, hundred, ... thirty, twenty)

Here is the answer. Sorry for the extra spaces :) private static String spellNumber(String number) { HashMap level1Num = new HashMap(); level1Num.put(1, " one "); level1Num.put(2, " two "); level1Num.put(3, " three "); level1Num.put(4, " four "); level1Num.put(5, " five "); level1Num.put(6, " six "); level1Num.put(7, " seven "); level1Num.put(8, " eight "); level1Num.put(9, " nine "); level1Num.put(10, " ten "); level1Num.put(11, " eleven "); level1Num.put(12, " twelve "); level1Num.put(13, " thirteen "); level1Num.put(14, " fourteen "); level1Num.put(15, " fifteen "); level1Num.put(16, " sixteen "); level1Num.put(17, " seventeen "); level1Num.put(18, " eighteen "); level1Num.put(19, " ninteen "); HashMap level2Num = new HashMap(); level2Num.put(2, " twenty "); level2Num.put(3, " thirty "); level2Num.put(4, " fourty "); level2Num.put(5, " fifty "); level2Num.put(6, " sixty "); level2Num.put(7, " seventy "); level2Num.put(8, " eighty "); level2Num.put(9, " ninty "); String output = ""; while (number.length() > 0) { String block; if (number.length() % 3 == 0) { block = number.substring(0, 3); } else { block = number.substring(0, (number.length() % 3)); } if (block.length() > 2) { output += level1Num.get(Integer.parseInt(block.substring(0, 1))) + " hundred "; number = number.replace(block.subSequence(0, 1), ""); block = block.replace(block.subSequence(0, 1), ""); } int block2 = Integer.parseInt(block); if (block2 = 7 && number.length() = 4 && number.length() <= 6) { output += " thousand"; } number = number.replace(block, ""); } return output; }

if(false)

Kind of a trick question. Finally block is always code if the try block is executing, only way to guaranty finally is not called is to not enter the try block.... or pull the plug on the JVM

Its just to check logic, finally will not run if system.exit(0) is called.

div.chess-row { height:35px; } div.chess-column { height: 35px; width: 35px; display: inline-block; border:solid 1px black; } div.chess-column.black-cell { background-color:black; } for(var i=1;i

div.chess-row { height:35px; } div.chess-column { height: 35px; width: 35px; display: inline-block; border:solid 1px black; } div.chess-column.black-cell { background-color:black; } Js:- for(var i=1;i<=8;i++) { var chessRow=document.createElement("div"); chessRow.classList.add("chess-row"); chessRow.classList.add("chess-row_"+i); document.querySelector('body').appendChild(chessRow); for(j=1;j<=8;j++) { var chessColumn=document.createElement("div"); chessColumn.classList.add("chess-column"); if(((i+j)%2)==0) { chessColumn.classList.add("black-cell") } document.querySelector('body .chess-row_'+i).appendChild(chessColumn); } }

Using a loop and mod function, obvs.

Could you give us a bit more information about the problem? Did you have to write a full solution from scratch, or just implement the method that finds the usage per month? Also, were the readings given as a list or as a stream which would constantly give you readings?

My answer was insufficient because I did not write enough tests (though I wrote some, so bear that in mind)

How much time it takes to complete the interview procedure? How can we know whether we cleared the first level or not

I was able to answer most of them.