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## Top Interview Questions

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13 Nov 2014
 Sum the odd integers between 1 and 100. Roll two die, what is the probability that the sum of the pips on the die are at least 9. There is a car auction. The price of the car is uniform [0,1000], you do not know the actual value of the car. If you bid higher than the value of the car you get it, if you bid lower than the value of the car you don't. If you know you can sell it on afterwards for x times its worth, what should you should you bid when: x=1.5 x=2.5 e.g. for x=1.5, you bid 100, the car is worth 80, you get it and sell it on for 120, which is a 20 profit. What is the next date that the day month and year share no common values. e.g. 13/11/2014 has four '1's so doesn't count.3 Answers2500 5/18 x=1.5, bid 0 x=2.5, bid 1000 17/06/2345your second answer is meant to be 5/21The first answer is also wrong. You should simplify for 1+99 = 100, 2+98 = 100 etc until only 50 and 100 are left then 49 * 100 = 4900 and finally 4900 + 50 + 100 = 5050.

24 Oct 2013
 At the bus stop 3/4 of commuters leave the bus and 7 new come in. This process repeats 3 times. What is the minimal number of people initially in the bus.3 Answers520.25(0.25 (0.25 x + 7) + 7) = x/64 + 7/16 + 7/4 is an integer, thus the minimum x is 52. Any quicker solution?Yup, there is a quicker solution. First note that if x is the answer, then the number of people on the bus is always a linear function of x => we are looking for the smallest possible number of people in the end. If the number of people in the end is y, then the number in the beginning is 4(4(4(y-7)-7)-7)=64y-588. Hence y is at least 10, and in that case the minimum x is 52. It remains to check that 52 works, and it does. This isn't a radical change from your solution, but multiplication is usually easier than division, especially considering that this is probably a first-round problem, where no pen/paper are allowed. Another method: First step subtracts 7 from y, so y>6. Second step requires 4y>35, or equivalently y>8. Finally, y=9 doesn't work and y=10 does, so x=52.

27 Dec 2017

15 Sep 2011
 Today is 15/09/2011,what's the nearest day in the future that all the eight digits are unique?3 Answers06/17/2345 not sure thoughI got the same. 06/17/23451st digit has to be 0 or 1, 3rd digit has to be 0, 1, 2, or 3. If 3rd digit is 3, 4th must be 0 or 1, which means you must 24XX is the earliest year you can try. So start with 1 and 0 both in either 1st or 3rd digit. Then earliest year is 2345. Earliest month is 06 Earliest day is 17 done