First round is pattern based question like..
n=1 n=2 n=3
* * *
*** *** ***
* *
* *
***** *****
*
*
*
*******

Question

First round is pattern based question like..
n=1                   n=2                                    n=3
  *                            *                                           *                 
***                        ***                                      ***
                                *                                           *  
                                *                                           *
                            *****                                   *****
                                                                              *
                                                                              *
                                                                              *
                                                                       *******

Samanvya Singh · Accepted Answer

d
if(n==1):
    l=n;m=n+1
    for k in range(n+1):
        for b in range(l):
            print(end=" ")
        l=l-1
        if(m>=2):
            for b in range(3):
                print("*",end=" ")
            m=m-1
        else:
            for b in range(3):
                print("*"*3,end=" ")
        print(end="
")
        
elif(n==2):
    l=n;m=1
    for k in range(n+1):
        if(m<3):
            for b in range(l):
                print(end=" ")
            for b in range(2):
                print("*",end=" ")
            m=m+1
        else:
            for b in range(l-2):
                print(end=" ")
            for b in range(2):
                print("*"*5,end=" ")
        print(end="
")
                
elif(n==3):
    l=1;m=1
    for k in range(n+1):
        if(m<4):
            for b in range(l):
                print("*",end=" ")
            m=m+1
        else:
            for b in range(l):
                print("*"*7)
        print(end="
")
(Code in Python)

Ujjwal Bansal · Answer

def show1(n):
    m=4-n
    for _ in range(0,n):
            print(end=" "*n)
            print("*"*m,end="
")
    for _ in range(m):
        print("*"*(n*2+1),end=" ")

mohd Shadab · Answer

if n=1 : program in C language
#include
void main()
{
	int i,j,n;
	printf("enter the value of n  : ");
	scanf("%d",&n);
	for(i=1;i<=n;i++)
	{
		for(j=1;j

Mohammad Ahkam · Answer

import java.util.Scanner;
class pattern8
{
	void print1(int n)
	{
		for(int p=0;p

vikash · Answer

n=int(input())
if n==1:
    for i in range(n+1):
        print("  " *(n-i)+"*"*(3*n+6*i))
elif(n==2):
    for i in range(3):
        for j in range(13):
            if(i in {0,1} and j in {3,5}):
                print("*",end="")
            elif(i==2 and j in {1,2,3,4,6,7,8,9,10,11,12}):
                print("*",end="")
            else:
                print(" ",end="")
        print()
elif(n==3):
    for i in range(4):
        for j in range(6):
            if(i in {0,1,2} and j==0):
                print("*",end="")
            elif(i==3 and j in {0,1,2,3,4,5}):
                print("*",end="")
            else:
                print(" ",end="")
        print()
else:
    print("",end="
")

WebKul

WebKul interview question

Interview Answers

Followed companies

Job searches

Bowls

Want the inside scoop on your own company?