Check if a String contains a number or not

Question

Anonymous · Accepted Answer

ATOI conversion .

Narendra · Answer

String s= "abcabddd1";
		char[] ch=s.toCharArray();
		for(char c:ch){
			if(Character.isDigit(c)){
				break;
			}
			
		}

Someone that I used to know · Answer

// Remember that the character "0" has the ASCII value 48
// so if we subtract 48 from every ASCII value we got
// and find a value between 0 and 9, means we got our number ;) 

    char s[] = "abc123def456g7h8i90";

    for (int i = 0; i = 0 && diff < 10) {
            return true;
        }
    }

Derpina · Answer

C++ solution:

bool containsNumber(string s)
{
   if (s.find_first_of("0123456789") != string::npos)
   {
      return true;
   }
   
   return false;
}

Alex · Answer

//Check if a String contains a number or not
function find_digit(str) {
	var search_result = str.search(/[0-9]/g);
	if (search_result < 0) {
		// or return false
		return console.log("nothing");
	} else {
		// or return true
		return console.log(str[search_result]);
	}
}

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