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      Senior Data Scientist Interview

      19 Oct 2023
      Anonymous interview candidate
      Singapore
      No offer
      Positive experience
      Difficult interview

      Application

      I applied online. The process took 3 days. I interviewed at Agoda (Singapore) in Oct 2023

      Interview

      I applied through linkedin and they sent an email with a link to a coding test. There were 3 medium difficulty leetcode questions. The time limit was 5 hours. I could not complete the 3 questions.

      Interview questions [3]

      Question 1

      Problem Description: You are standing on a unique diamond-shaped platform composed of 5 tiles. These tiles are positioned at coordinates: (-1,0), (0,-1), (0,0), (0,1), and (1,0). From a starting position (xs,ys), you make random moves in one of four directions: left (decrease x by 1), right (increase x by 1), up (increase y by 1), or down (decrease y by 1). Each direction has the same probability and the direction of each move is entirely independent of previous moves. Determine the probability that you can reach a given destination (xe,ye) without stepping off the diamond platform. Constraints: (xs, ys) must be one of: (-1,0), (0,-1), (0,0), (0,1), (1,0) (xe, ye) must also be one of the above coordinates. Starting and ending coordinates are distinct: xs != xe or ys != ye Input: A single line containing four integers, denoting xs, ys, xe, ye respectively. Output: A single line showing the probability that you'll reach the destination before stepping off the platform. Sample input: -1 0 0 0 Sample Output: 0.25 Explanation: From the starting position, you have a 25% chance of moving right (and thus reaching the destination). Any other move would result in falling off the platform. [execution time limit] 4 seconds (py3) [memory limit] 1 GB [input] integer xs The x-coordinate of the starting position. [input] integer ys The y-coordinate of the starting position. [input] integer xe The x-coordinate of the end position. [input] integer ye The y-coordinate of the end position. [output] float Probability to reach end position before falling of platform.
      Answer question

      Question 2

      Problem Statement: You are given a starting number of 1. Your task is to reach a target number, t, using two available operations: operator_add: Adds a fixed number, x, to the current number. operator_multiply: Multiplies the current number by a fixed number, y. The objective is to reach the target number, t, by using these operations sequentially. Among all possible ways to reach t, pick the sequence that Maximizes the number of times operator 2 is applied Minimizes the number of times operator 1 is applied among all sequences that maximize usage of operator 2 Constraints: 1 ≤ t ≤ 10^20 1 ≤ x ≤ 1000 2 ≤ y ≤ 1000 Input Format: Three integers: t, x, and y. Output Format: If a solution exists: A list of strings where each string represents an operation followed by the number of times it is applied. The solution should be compact in the sense that consecutive occurrences of the same operator collapse to 1 element in the list. This means that if an element in the list correspond to "operator_add", then the next one should correspond to "operator_multiply" and vice versa. For example, if you want to apply the sequence "operation_add, operation_add, operation_multiply, operation_multiply, operation_multiply, operation_add", then the output should be: ["operator_add 2", "operator_multiply 3", "operator_add 1"]. If no solution exists: A list with one element: "no_solution". Examples: Input 1: t = 54, x = 1, y = 3 Output 1: ["operator_add 1", "operator_multiply 3"] Explanation: Starting from 1, add 1 once to get 2, then multiply the result by 3 thrice (2*3^3 = 54) to get 54. The sequence thus results in the target number. Using operator 2 at least 4 times will result in a number bigger than 54 (3^4 > 54). Hence operator 2 can maximally be used three times. For operator 2 being used three times, operator 1 needs to be used at least once because 3^3 is not equal to 54. Therefore it minimizes the usage of operator 1. Input 2: t = 3 x = 4 y = 4 Output 2: ["no_solution"] Explanation: Both operators increase the number and applying any operator once already results in a number that is too big. [execution time limit] 4 seconds (py3) [memory limit] 1 GB [input] integer64 t Target number: the number you want to reach by sequentially applying the operators. [input] integer64 x By how much you increase the current result if you apply operator1. [input] integer64 y By how much you multiply the current result if you apply operator2. [output] array.string List of strings where element i equals "operator_add" or "operator_multiply" followed by how many times you want to apply it. In case there is no solution, output is ["no_solution"].
      Answer question

      Question 3

      You want to buy a billboard featuring the name of your company. The price of the billboard is the sum of the price of the letters in your company name. For example, the price of company name "aga" is two times the price of letter "a" plus the price of letter "g". You don't know the price per letter, but you do know the prices of other company names. Can you derive the price of your company name? A company name only contains letters from the alphabet. There are 26 different letters and they are all lower case. You are given: your_company_name: a string representing the name of your company other_company_names: a list of strings where each element is the name of another company other_company_prices: a list of real numbers where other_company_prices[i] is the price of other_company_names[i] Return the price of your company name if it can be derived, otherwise return -1 Constraints: The length of a company name is maximally 100 len(other_company_names) = len(other_company_prices) <= 100 For each price in other_company_prices: -10^6 <= price <= 10^6 Sample Input: your_company_name = "aabc" other_company_names = ["ab", "ac", "bd"] other_company_prices = [99.5, 1000.2, 2000.8] Sample Output: 1099.7 Explanation: The letters in "aabc" is the union of the letters in "ab" and "ac", hence the price is the sum. Sample Input: your_company_name = "d" other_company_names = ["aab", "acc"] other_company_prices = [500, 6000] Sample Output: -1 Explanation: The letter d doesn't appear in any other company name and therefore we cannot derive its price. [execution time limit] 4 seconds (py3) [memory limit] 1 GB [input] string your_company_name String representing the name of your company [input] array.string other_company_names List containing the names of other companies. [input] array.float other_company_prices List where element i contains the prices of other_company_names[i] [output] float Price of your company
      1 Answer
      5

      Other Senior Data Scientist interview reviews for Agoda

      Senior Data Scientist Interview

      5 Feb 2024
      Anonymous interview candidate
      Singapore
      No offer
      Positive experience
      Difficult interview

      Application

      I applied online. I interviewed at Agoda (Singapore)

      Interview

      First Round - data structure coding test in code signal - five hours time limit Three data structure problem. Scored around 600/900 (300 for each question). Did not get accepted to next round.

      Interview questions [1]

      Question 1

      Coding questions with prob and optimization
      Answer question
      2

      Senior Data Scientist Interview

      3 Nov 2023
      Anonymous interview candidate
      Bangkok
      No offer
      Negative experience
      Easy interview

      Application

      I interviewed at Agoda (Bangkok)

      Interview

      5 rounds, poor competence, they lie, ignore and think that everyone owes them, I don’t recommend wasting time here, I abandoned this track in the second round, all the signals were bad

      Interview questions [1]

      Question 1

      typical problems from a leetcode (not data science)
      Answer question

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